Print details of customers with less than given account balance

Write a 'C' program to accept customer details such as: Account_no, Name, Balance using structure. Assume 3 customers in the bank. Write a function to print the account no. and name of each customer whose balance < 100 Rs.

Solution:

#include<stdio.h>
/* Defining Structre*/
struct bank
{
     int acc_no;
     char name[20];
     int bal;
}b[3];
/*Function to find the details of customer whose balance < 100.*/
void check(struct bank b[],int n) /*Passing Array of structure to function*/
{
     int i;
     printf("\nCustomer Details whose Balance < 100 Rs. \n");
     printf("----------------------------------------------\n");
     for(i=0;i<n;i++)
     {
          if(b[i].bal<100)
          {
               printf("Account Number : %d\n",b[i].acc_no);
               printf("Name           : %s\n",b[i].name);
               printf("Balance        : %d\n",b[i].bal);
               printf("------------------------------\n");
          }
     }
}
int main()
{
     int i;
     for(i=0;i<3;i++)
     {
          printf("Enter Details of Customer %d\n",i+1);
          printf("------------------------------\n");
          printf("Enter Account Number : ");
          scanf("%d",&b[i].acc_no);
          printf("Enter Name           : ");
          scanf("%s",b[i].name);
          printf("Enter Balance        : ");
          scanf("%d",&b[i].bal);
          printf("------------------------------\n");
     }
     check(b,3);           //call function check
     return 0;
}


Output:

customers account balance
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