Answer: d. 6237 sq.m.
Explanation:
Border of the semi-circular piece of land means perimeter of the garden.
Perimeter of a semi-circle = πr + 2r
∴ πr + 2r = 324
∴ r(π+2) = 324
∴ r ( | 22 | + 2) = 324 |
7 |
∴ r ( | 36 | ) = 324 |
7 |
Area of semi-circle garden = | 1 | πr2 = | 1 x 22 | x 63 x 63 = 6237 sq.m. |
2 | 2 x 7 |
Answer: b. 1680 m
Explanation:
We know that, Time = | Distance |
Speed |
Speed = 60m/min = | 60 | m/sec = 1 m/sec |
60 |
∴ | 2πr | - | 2r | = 60 minutes |
1 | 1 |
∴ 2r ( | 22 | - 1) = 3600 seconds |
7 |
Answer: a. 432 sq.cm.
Explanation:
Diameter = 8cm; So, radius = 4cm
Inscribing triangle in semicircle means having all vertices of triangles touch or lie on the border of the semicircle.
Area of triangles = 3 x area of equilateral triangle = 3 x | 3 | (side)2 |
4 |
∴ Area = 3 x | 3 | (4)2 = 123 = 144 x 3 = 432 sq.cm. |
4 |
Answer: d. 28cm
Explanation:
Length = L and breadth = B
Perimeter = 200 = 2(Length + Breadth)
∴ 200 = 2(L + L - 12)
∴ L = 56cm
∴ B = L - 12 = 44cm
Area of rectangle = L x B = 56 x 44 = Area of circle
∴ 56 x 44 = πr2 = | 22 | r2 |
7 |
∴ r2 = | 56 x 44 x 7 | = 784 |
22 |
Answer: c. 16π
Explanation:
We know,
Area of circle = Area of Square
∴ πr2 = (side)2
∴ side = π x r = π x | diameter | = 4π |
2 |